Slope is change in y over change in x.

So the units of y are 1 over molarity, a concentration unit.

The units for x was in seconds.

So, this gives me 1 over molarity times seconds for the slope.

I mean, for the rate of constant k and that's always a unit for

second order reaction.

So now, we've answered part two.

Part three tells me that the initial concentration of A is 0.1.

So we can use our equation to calculate A at that time,

because what we want to know is what percent reacted after five seconds.

So if we knew how much was remaining,

we'll be able to get the percent that reacted.

So, we will plug in our k of 0.0296.

We will put in our time of 5 seconds and

we will put 1 over our initial concentration.

This will give me 1 over A.

If we multiply this out and add this number here,

we get a value of 1 over A equals 10.148.

So A would be the reciprocal of that,

which is 0.0985.

Now, that is not the answer to the question.

The question says, what percent of A will react?

So, let's figure out how much actually reacted.

Well, if we start with point one and

we finished with 0.0985.

We will have a value

of 0.001 molar

that reacted.

So, so much we start with.

So, much we finish with.

We subtract that, this is how much had to have reacted.

So, what percent reacted?

That percent reacted is 0.001 and I can only know

that's the 1 decimal place, because I can only keep 3.

I mean, one significant figure, because I can only keep three places to the right

of the decimal point according to the rules of addition and

subtraction in significant figures.

So, the percent reacted would be the amount that reacted

over the amount that I started with times 100 and

that will give me 1% reacted.