So, I'll make a note, not quite. To go from Vm1 to Vm2, go from Vm1.
To Vm2. You need use n1, n1, and h1.
That is to say, not the original values of n, m and h, but the new values of n, m,
and h. And if you do that, you should be able to
get it just fine. Let me say another word here just about
the synchronization of all these calculiza, calculations.
You will find, I believe that if you start off with Vm, start off with Vm, n, m, and
h, and use this set of values to get Vm1. And use start with these values, get Vm1.
Start with these same values, get n1, m1, and h1.
Your life will work out a lot better than if you do the following algorithm starting
with Vm, n, m, and h to get Vm1, and then use Vm1 to get n1, m1, h1.