We have i sub L At t = 0-.

And that's what our circuit looks like before

the switch is thrown, before this circuit is complete

on the right-hand side of our 2 amp source.

So to find i sub L at t = 0-, we simply use current division between R1 and R2.

We know that the 2 amp source is going to be split between R1 and

R2 depending on the values of R1 and R2.

So i sub L, at (t = 0-) = 2 amps,

and again it's divided between R1 and R2.

So it's going to be 2 amps (R1/R1 + R2).

That's our current i sub L at t = 0-.

So the second part of this question is to find i sub L at t = infinity,

in other words, a long time after the switch has been thrown.

So in order to find that,

we have to first of all, we draw our circuit for that condition.

So we have our 2 amp source which hasn't changed,

we have our switch which is thrown in this case,

so it's closed, we have a closed switch.

We still have our resistor R1, our inductor acts as a short

circuit in a steady state, and we have a resistor R sub 2.

And so we have a circuit,