The topic of this problem is Ohm's law, and also using the well-known power equation. The problem itself is to determine the current and the power absorbed or supplied by the 2 kilo-ohm resistor. So, we want the current through the resistor, and we want the power associated with the resistor, and to determine whether it's absorbed or supplied power. So to do this, we use Ohm's Law first to determine the current. If we use Ohm's Law and solve for the current, then we have current is equal to 12 volts divided by 2 killoohm's of resistance. And so ultimately, we end up with a current equal to 6 miliamps of current. So that solves for our current. And our current is a positive current, in this case as well. The next thing we want to do is we want to determine the power across the 2k, or associated with the 2 kilo-ohm resistor. And so, the power is going to be determined by looking at the current through the resistor and the voltage across the resistor. We determine the voltage across the resistor using Ohm's Law, but we also are using loop analysis. But we also have to use the passive sign convention. The passive sign convention tells us that the current is assumed to enter the positive side of the voltage polarity on an element. It's, the passive sign convention is absolutely critical to determine power flow in a circuit. And so, in this case, if we assume that the current is entering the positive polarity of the voltage drop across the 2 kilo-ohm resistor, then we would then assign the polarity as shown across the 2 kilo-ohm resistor. And so, if we're looking for the power, the power is going to be, in this case, the voltage which is across the 2 kilo-ohm resistor, which is going to be 12 volts, Times the current. And the current is 6 milliamps. So, ultimately, we end up with 72 milliwatts, Of power. And that's a positive power. So, if we're looking for whether it's absorbed or supplied, then we see then it's a positive power, and so we can then say that 72 milliwatts is absorbed by the 2 kilo-ohm resistor.