[SOUND] Let's work Algebraic Symbol Manipulation.

[SOUND] For example, let's solve the following equation for F.

Right now we have C is equal to something and we want to manipulate this equation

to get F is equal to something instead. And we'll begin by multiplying both sides

of the equation by 9/5 in order to get rid of this fraction here.

That is, we have 9/5 * C = 9/5 * 5/9(F-32).

And 9/5 * 5/9 is 1, so this fractions will cancel which leaves us with 9/5C = F

- 32. And now we'll add 32 to both sides of the

equation, which gives us 9/5C + 32 = F - 32 + 32.

And -32 + 32 will cancel. They add together to give us 0, which

leaves us with F = 9/5C + 32, which would be our answer.

By the way, these are the equations that we use to convert between Farenheit and

Celcius. It's temperatures.

All right, let's see another example. [SOUND] Let's solve the following

equation for y. What we can do is we can start by

multiplying both sides of the equation by this denominator here, y - 3.

3, which gives us x(y - 3) = (3y + 2) / y - 3 * (y - 3).

And now the y - 3 is on the right. We'll cancel, and we are assuming here of

course that y does not equal 3, which leaves us with x(y - 3) = 3y + 2.

And now let's distribute this x to both of these two terms, which gives us xy -

3x = 3y + 2. Now remember that we want to solve this

equation for y. So let's bring all the ys to one side and

everything else to the other. Which gives us xy - 3y = 2 + 3x.

And now we'll factor y out of both terms on the left.

Which gives us y(x - 3) = 2 + 3x and now let's divide both sides of the equation

by (x - 3). And, the (x - 3)s on the left will

cancel. And, we're assuming here, of course, that

x does not equal 3. Which leaves us with our answer of y = 2

+ 3x / x - 3. This is how we algebraically manipulate

an equation to solve for a variable. Thank you and we'll see you next time.

[SOUND]