Okay, so let's look at this one here.
It's an aldehyde.
So here you have C and 3CH3 groups and they're all going to be equivalent.
They're all in the same chemical environment.
And then you have the H of the aldehyde group.
So you expect peaks.
You expect two peaks, you have two distinct chemical environments so
you expect two peaks and the ratio of a 9 to 1.
And here actually in this spectrum when it was done it's recorded
in the integration that measured the peak intensities.
And you can see here the peak intensity is 17.3 to 255.4 which is about 9 to 1.
So you can initially say this is due to the nine protons form the methyl groups.
And this one here, which is widely deshielded,
is due to the aldehydic H group and so forth.
Let's do the last ones.
Here you have this is a nitine group here.
So, you have a methyl groups.
These are equivalents.
So, there are six there.
There's one there and there's a one that's attached to the triple bond.
Carbon, carbon triple bond.
So, you'd expect three environments and as you can see, you do.
Here you have nine and here you have one each.
So this large peak here is due to the nine protons.
Sorry that's six.
CS3, so six.
And these ones here are due to the H1s of the oxygen and the h1s of the C.
And again they're difficult to assign these, but
again you have the more likelihood of negative oxygen.
So you might expect that the more deshielded one,
the one to higher chemical shifts is due to this and
the other one, the less shielded one is due to this proton here.