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Okay. Welcome back.
Hopefully, that was a pretty simple exercise.
So, we saw that under study state conditions we know that all time
variables are steady for the viewer. So, all time variant terms, like this
control volume term here, would be set equal to zero for the steady state
condition. If you have a system that's adiabatic you
would set all heat transfer terms equal to zero.
And again they don't alwyays happen at the same time.
You don't always involve both of those assumptions together.
But they're both pretty common. And in fact what we're going to look at
now are a number of very common flow devices.
Steady state steady flow devices well we're going to see those two assumptions
alot. So in fact we're going to say these
aren't just simple flow devices. We're going to call all of these devices
simple steady-flow devices. So this is a conservation of energy in
its most general form. As we've learned how to use these tools,
like the conservation of mass and the conservation of energy, I want you to
write out the four most generic, most general form of the expressions every
single time. It's going to be your instinct to try and
simplify these on the fly, so you simplify them as you're writing them
down. Oh yeah, and I'll invoke this, and I'll
assume there's one exit and two entrances, or things like that.
And that type of work, once you're. Once you've had a lot of experience
that's fine to use those type of methods, but for now when you're just getting
started with the introduction to these tools it's better to be very very careful
and very very rigorous. So we're going to use these big forms of
these expressions every time, as we get a feel for how these devices perform and
what are some of the governing principles for the devices, okay.
So we're going to start. We're going to look at like five or six
different categories of flow devices. We're going to assume every one of these
devices is steady flow. So for every one of these, that steady
flow and steady state. And you say, what's the difference?
Steady state addresses the time variable. Steady flow is really saying that we have
steady uniform conditions at the entrances and exits.
So that we can in fact define thermodynamic properties.
If they're undefined, like if something's changing and it's unsteady flow And I
can't define all velocity or a pressure or a temperature.
So that's, these are very specific assumptions that we're going to invoke
for all of these flow devices. And these are velocities, again just to
remind ourselves, those are velocity terms there.
So for nozzles and diffusers, these are simple systems that we'll find a lot of
flow systems you'll find them in agriculture.
You'll find them in turbo machinery like you find in power plants.
You'll find them in common, household devices.
You'll have nozzles and diffusers on your faucets on your hoses all sorts of
places. So a nozzle is a contracting surface, and
a diffuser is an expanding service. I'll draw them like this, and we always
want to get into the practice of again identifying what the system is, so we'll
draw our control volume around our nozzles.
So this my nozzle here and this is my diffuser over here.
And I always think the best example that most people understand right away.
For a nozzle, is imagine putting your thumb over the end of a garden hose.
That's a nozzle and you think to yourself, okay, is there any work
transfer in this process? So, look for mentally go through your
checklist. Are there any shafts portruding into or
out of the system? Do I have any electrical cords?
Hopefully not near water. In the into or out of the system.
You're like, nope, nope. You go through the checklist.
Expansion or compression? No, these are rigid control volumes.
So the volumes are fixed, so there's no expansion or compression work.
So both my nozzles and diffusers have, by definition, no work associated with that.
The other thing I wanted you to think about is when we consider heat transfer,
you have to consider heat transfer through the system boundary, and a couple
of, again we've seen the approximation of when things are adiabatic.
What does it do to the control conservation of energy.
Well, we've applied this simplification, the steady state simplification.
when we consider the heat transfer, you have to consider things like well, what
are the, when you become more advanced in your heat transfer analysis, you'd think,
Okay. What are the temperature differences that
we're considering? What are the mechanisms, convective,
conduction, radiation. And one of the things you have to
consider, the radiation is scales based on temperature to the fourth.
So low temperature systems have very low radiation in general.
So I'm left with conduction and convection, and some of the issues
associated with those, the fundamental physics associated with convection and
conduction are the speed of the fluid [COUGH].
If the fluid is moving, you tend to be dominated by convection and conduction
can be neglected. And then when you look at convection, you
also have to consider how long does the fluid have within the control surface to
transfer heat. So imagine your body is at 98.6 degrees.
Do you physically change the temperature of the water as it extis the hose.
The answer is, probably not. The contact exposure is so short, a short
period of time. That it's unlikely that you're changing
the temperature in the fluid. So, even though your temperature is
different than the temperature of the water flowing in the hose, is not a large
heat transfer. In that system, the nozzle system is
considered adiabatic, and same with the diffuser, for sort of the inverse
rationale. the other key properties that we need to
understand about nozzles and diffusers. So the purpose of the nozzle is generally
to accelerate the flow. So if we say this is the exit state here
and if this is the entrance state so the fluid is moving like this and the
diffuser of the fluid moves like this. The entrance state, the exit state, and
some of the things that we know about these systems is that, again, the purpose
of the a nozzle is to accelerate the flow.
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we generally approximate the turbines as being adiabatic, and I've already
mentioned once before. There's actually a lot of heat transfer
that happens between turbines and compressors and pumps as well.
The issue is those heat transfer rates are actually very small, relative to the
other energy transfer rates in the system.
So, this is, really what we should be saying, we call them adiabatic.
In, in reality, it's negligible, relative to the other energy transfers.
And we're going to do an example on this shortly to show you exactly what we're
talking about here, in terms of the relative magnitude of the terms.
if you ever seen a turbine, they generally don't have a whole lot of
vertical movement in the fluid. Some can be pretty big.
They can be a story or too tall, but again, not a whole lot.
So these, they have negligible potential energy changes, and what we're left with
is essentially that the work transfer is balanced by the mass transfer, and again
because its a control volume, we have enthalpy instead of internal energy and
I'm going to leave those kinetic energy terms in there.
What we're going to find is that the kinetic energy, while it seems like that
would be a potentially really large contribution, it actually isn't.
So what we'll alternately find is that, so, and we'll prove this to you here
shortly, is that the work transfer for a turbine is simply governed by the mass,
mass flow rate times the enthalpy difference between the inlet and the
outlet. So hn minus h exit or h out, or how,
whatever exit term you want to subscript you want to use to make that notation.
But it's simply a difference between enthalpy in and the enthalpy out.
So, those are turbines. Compressors and pumps are the inverse to
turbines. So they're just like nozzles have their
mirror image in diffusers. Turbines have their mirror image in
compressors and pumps. So compressors because they are mirror
images we like to denote them using a trapezoid reflected around that axis
here. And we would have, again, flow-in,
flow-out of my turbine. We'll call this state one, we'll call
this state two. The purpose of a compressor and a pump is
exactly what the names imply. The compressor is to increase the
pressure. It's actually to increase the internal
energy of the fluid. And same with the pump.
It's to increase the pressure or the internal energy associated with the
fluid. Some folks get really rigorous about
saying compressors are only associated with gases, that pumps are only
associated with liquids. I tend to be a little bit more flexible.
I quite often call pumps, devices that actually compress gases.
So again I'd encourage you to be kind of flexible yourself, in your interpretation
of what does it mean, when I call something a compressor a pump.
The purpose of the device is to increase the energy, the internal energy, the end
enthalpy thereby enthalpy of the fluid. So that's its purpose, and whether or not
its liquid phase or gas phase really depends on what the fluid is.
Okay, so again we're going to draw our control surface just like we did before,
and if I start with a low energy fluid on one side and end up with a high energy
fluid on the other side. And if it's like its sister device, the
turbine, where it's adiabatic, so we're going again assume adiabatic, well then
you better go through the math and say, hey, in order for that to be consistent
with the conservation of energy, this has to be a system where it works into the
compressor or the pump. Okay.
So we know for compressors and pumps we're going to have work in.
Also, you'll see a pump represented with this sort of a schematic type form.
So you'll see again, state one, there's the inlet state.
And here's state two. And again, be flexible on your
interpretation here. So, this is work into the pump.
and again, these systems are considered adiabatic.
So, if this is the conservation of energy, invoking a few assumptions, for a
turbine. Then we know for a pump or a compressor,
that it's going to have the exact same expression, except we're going to have
reverse signs. Okay, because remember, we like work out
in the power generation sector, we like to see work out as a positive number.
This is a high energy state going into a turbine.
This is a low energy state coming out of it.
So this number's going to be positive. Work out is positive.
For this pump, we know we're going to have the exact same governing equation,
except we're going to have h in minus h out, but this term will now be negative.
Because the high-energy term is associated with the exit state, and the
low-energy term is associated with the entrance state.
And I've mentioned multiple times, we're very notation intense in this class.
We like subscripts, and superscripts, and accents on top of our variables, and they
all have specific meaning. Having said that, I also want you to be
flexible on, is it an inlet, is it an outlet, is it an exit, is it a one or
two, any of those is fine. What I want you to do is just be able to
recognize what's into the system and what's out of the system.
So there isn't a convention, or a standard convention, for in/out.
Like what's the right notation? There is no right subscript notation,
except for the one that you apply and just make sure you use it consistently,
right, throughout your analysis. Okay, that again will develop those tools
through example or kind of develop that, habits I should say, you will develop
good habits and how to make these notations.
Okay, so the last one that I wanted to consider today.
Actually second to last, I apologize. There's one more I want to squeak in, is
a heat exchanger. So a heat exchanger the whole purpose of
the device is to move heat transfer energy, move energy from one fluid to
another by heat transfer. So the simplest way we can represent a
heat transfer device, our heat exchange is, we'll just do this simple counter
flow, and you're going to have flow into the system on one side, and out of the
system on the other. And we'll do a nice little counter flow
heat exchanger here so we have two fluids, we're not going to allow them to
mix. We're going to say they can't mix in this
example, and Work in a move these fluids past each other, and we're going to have
conduction and convection heat transfer through the walls of the heat exchanger.
So we're going to move energy from one fluid to another.
Let's call this top fluid the hot fluid, and we're going to call this the cold
fluid here. And that allows us to go if the hot fluid
is on the top in the cold fluids on the bottom Then the heat transfer has to
occur in this direction, ok. heat exchangers by definition do not
require any work so there is no, we're not going to use any electrical heating
or anything like that. We're going to allow these heat
exchangers to exchange heat through convection and conduction, no shafts,
nothing like that. So if I chose to draw the boundaries like
this. The control volume around the entire heat
exchanger. Two key outcomes happen.
One is, the work transfer for that system is zero.
The other thing is, and this is really important conceptually, there's no heat
transfer with the ambient. That's a fundamental assumption of a heat
exchange. All the heat transfer occurs between the
hot and the cold fluid. So in this control volume, the system is
adiabatic. And this Q is only relevant If I chose
this to be my control volume, now you would go, oh, look there's energy
transfer across that control boundary. So for this system, the blue system, the
work transfer is still zero, but now I have a non-zero heat transfer.
So heat exchanges require you to be thinking.
Notice also in the blue control surface, I have the mass flow rate of one equal to
the mass flow rate of two. And I have energy transfer associated
with those fluids. In the red control volume, I have mass
transfer From both the hot fluid and the cold fluid.
So my continuity expression, the conservation of mass, for the red control
volume, is actually the mass flow rate at state 1 plus the mass flow rate at state
3. Has to be identically balanced by the
mass flow rate at state two and the mass flow rate at state four.
OK. So be careful how you choose your control
surface and whenever you look at the control surface you have to identify all
of the energy transfer and all of the mass transfer that cross the system
boundary. If they don't the system boudry, they're
interior. They're either completelly inside the
control surface, or completelly outside the control surface.
And either way, they will not be considered.
You don't have to consider those terms in your conservation equations.
Okay, so, Remember I told you there's parallels between conservation of mass
and conservation of energy. Well let's take the conservation of
energy, for this system. For the for the red system which includes
both fluids. Well again we've, there's no heat
transfer, across we've assumed the heat exchanger does not have (no period) You
know significant heat with the ambient or the environment and we're going to have
assume there's no work transfer and for these systems they're going to have
negligible kinetic and potential energy changes.
So these guys are going to neglect the changes in ke, kinetic energy and
potential energy. For heat exchangers.
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There's no heat transfer. Okay.
We're going to again neglect kinetic and potential energy changes.
We have one mass flow rate into and out of this system, and we look at the
conservation of energy. And, again, it's the same simplifications
we had for the heat exchanger, except now look what happens to the conservation of
energy. So we have m dot in, the mass flow rate
at the entrance times the enthalpy at the entrance, equals the mass flow rate at
the exit times the enthalpy at the exit, except, from the conservation of mass, we
know that the mass flow rates, there's just one mass flow rate in the system, so
we can cancel these. And what we end up with is a constant
enthalpy device. kind of a strange little world.
But throttles are isenthalpic. So there's a good word for you.
So again, just kind of a unique little simplification that happens with
throttles and valves that we need to be aware of.
we'll add some complexity to throttles later, but not right now.
But for conservation of energy, conservation of mass, couldn't be simpler
for throttles [UNKNOWN]. Okay, so I want to leave you with a
couple of thought questions. And I want you to come up with a, you can
either use a system example, you know, you can think of, you know, some actual
device. Or you can just think again in terms of
the generic forms, or the conservation of mass, and the conservation of energy.
I want you to answer these two questions. Can a system have unsteady mass-flow and
steady energy transfer? Can a system have both of those
assumptions happening simultaneously, or conditions happening simultaneously?
And, when can you have a system which has only flow in and no flow out?
So imagine a system that has one entrance, but no exits.
What's the condition that allows that to happen?
Think about those, come up with the answers and we'll talk about em next time.